Three moles of H2(g) and 3.00 moles of I2(g) are introduced into a 1-liter box at a temperature of 490°C. Find the concentration of each substance in the box when equilibrium is established.
The reaction proceeds to equilibrium and
At equilibrium, then,
[H2] = (3.00 − x) mol/L
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(where x is the number of moles of H2 that are in the form of HI at equilibrium)
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[I2] = (3.00 − x) mol/L
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(the same x is used since 1 mol of H2 requires 1 mol of I2 to react to form 2 mol of HI)
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[HI] = 2x mol/L
黃色的地方看不懂可以麻煩用文字解釋一下